First TCG product announced for 2012: Difference between revisions

I think this is what I'm supposed to do
(exciting!)
(I think this is what I'm supposed to do)
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userlink=User:Maverick Nate |
userlink=User:Maverick Nate |
tagline=Japanese 'Dragon Selection' subset arriving Jan. 27 |
tagline=Japanese 'Dragon Selection' subset arriving Jan. 27 |
blurb=The first TCG product for the new year has been announced. The Japanese 'Dragon Selection' subset will be arriving Jan. 27, and will exclusively contain holographic cards. }}
blurb=The first TCG product for the new year has been announced. The Japanese 'Dragon Selection' subset will be arriving Jan. 27, and will exclusively contain holographic cards.
 
Update: Yahoo! Shopping has labelled this set as "introducing the Dragon type". All Dragon-type Pokémon have already appeared in the TCG, suggesting that a new type is going to be introduced to the TCG.}}
{{CategorizeIn|TCG|10|11}}
{{CategorizeIn|TCG|10|11}}


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The first TCG product for the new year has been announced. The Japanese 'Dragon Selection' subset will be arriving Jan. 27. The pack artwork features {{p|Druddigon}}, {{p|Haxorus}}, and {{p|Rayquaza}}, and also promotes that all five cards in the packs will be holographic. The subset contains an unknown number of cards.
The first TCG product for the new year has been announced. The Japanese 'Dragon Selection' subset will be arriving Jan. 27. The pack artwork features {{p|Druddigon}}, {{p|Haxorus}}, and {{p|Rayquaza}}, and also promotes that all five cards in the packs will be holographic. The subset contains an unknown number of cards.


{{ud}}Yahoo! Shopping has labelled this set as "introducing the Dragon type". All Dragon-type Pokémon have already appeared in the TCG, suggesting that a new type is going to be introduced to the TCG.
{{ud}}Yahoo! Shopping has labelled this set as "introducing the Dragon type". All {{type|Dragon}} Pokémon have already appeared in the TCG, suggesting that a new type is going to be introduced to the TCG.


==Information==
==Information==